Question

If z-1/z = 8 then the value of z sq. +1/z sq. is​

Answer 1

Answer:

Given,

         $z - \frac{1}{z} = 8$

squaring on both sides,

         $(z - \frac{1}{z})^2 = 8^2$

by expanding the above we get,

         $z^2 - 2 * z * \frac{1}{z} + \frac{1}{z^2} = 64$

         $z^2 - 2 + \frac{1}{z^2} = 64$

         $z^2 + \frac{1}{z^2} = 64 - 2$

         $z^2 + \frac{1}{z^2} = 62$

                    Hope it helps you^_^