A current of 2A flows through a 12 V car headlight bulb for 6 minutes. How much energy occur in this time
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Answered by
14
T=6 minutes=6×60=360 seconds
E=I×I×V×T
E=2×2×12×360
E=48×360
E=17280J
E=I×I×V×T
E=2×2×12×360
E=48×360
E=17280J
piyushkumar154:
What
write the formula which is used to solve this qstn
Answered by
24
Current-2A
P.D.-12V
Time-6min.-6×60=360s
Resistance-P.D./Current
R-12/2
R=6
Energy = I^2RT
=2×2×6×360
=8640J
P.D.-12V
Time-6min.-6×60=360s
Resistance-P.D./Current
R-12/2
R=6
Energy = I^2RT
=2×2×6×360
=8640J
are u asking from me ????... formula = (current )square × resistance × time
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