Question

A current of 2A passes through a circuit for 1 min. If the potential difference in the circuit is 3V what is the work done in transferring the charges?

Answer 1

Answer:

The work done in transferring the charges is 360 Joules.

Explanation:

Given that,

Current in the circuit, I = 2 A

Time, t = 1 min = 60 s

Potential difference in the circuit, V = 3 volts

We need to find the work done in transferring the charges.

First we can find the magnitude of electric charge flowing in the circuit. It can be calculated as :

$q=I\times t$

$q=2\ A\times 60\ s$

q = 120 C

The electric potential difference is defined as the work done per unit charge. It is given by :

$V=\dfrac{W}{q}$

$W=V\times q$

$W=3\ V\times 120\ C$

W = 360 Joules

So, the work done in transferring the charges is 360 Joules. Hence, this is the required solution. Hence, this is the required solution.

Answer 2

Answer:

360 joules

Explanation:

I=2A

V=3v

T=60sec

w=?

w=VIT

=3×60×2

=360Joules