Question

A current of 3.2 a flowing in a conductor . the number of electrons flowing per sec across a given cross section of conductor will be

Answer 1

So, no of electrons=( 10C/1.6×10^-19 )=6.25×10^19 electrons. Therefor, 6.25×10^19 electrons will flow through a copper wire carrying 10amps current for 1sec. Thankyou!!

Answer 2

Answer:

$n=2\times 10^{19}$

Explanation:

It is given that,

Current flowing across the conductor, I = 3.2 A

Let n number of electrons flowing per second across a given cross section of conductor. The electric current is given by :

$I=\dfrac{q}{t}$

Also, q = ne, t = 1 s

$n=\dfrac{I}{e}$

e is the charge on electron

$n=\dfrac{3.2}{1.6\times 10^{-19}}$

$n=2\times 10^{19}$

So, $2\times 10^{19}$ of electrons are flowing across a given cross section of conductor.