Question

a two digit number is 4 times the sum of its digit and twice the product of the digit find the number

Answer 1

Let the digit at ones place be x and at the tens place be y
So the number will be = 10y+x
According to question
4(x+y) = 10y+x
4x+4y=10y+x
6y=3x....so. x=2y-------eq.(1)
Now in case2
2xy=10y+x
Putting the value of eq 1 we ger
2*2y*y=10y+2y
4y^2=12y
4y=12
So y=3
Put this value in eq(1)..so x=2y=2*3=6
So the number is 30+6=36

Answer 2

Answer:

Let the digit at ones place be x and at the tens place be y

So the number will be = 10y+x

According to question ;

4(x+y) = 10y + x

4x + 4y = 10y + x

6y=3x....so. x=2y-------eq.(1)

Now in case2

2xy = 10y + x

Putting the value of eq 1 we ger

2*2y*y=10y+2y

4y^2=12y

4y=12

So y = 3

Put this value in eq(1)..so x=2y=2*3=6

So the number is 30+6=36