Question

A current of 4.8 amp is flowing in a conductor.The number of electrons flowing per second through the conductor will be

Answer 1

Explanation:

I= Q/t. Q= n.e ( : n- no of electron and e- charge on 1 electron)

I= n.e/t then n=Ixt/e then

no.of electron calculated by:

n= 4.8x1/1.67x10^-19