Question

A current of 4 amp flows in a wire of resistance 60 ohm.calculate:
a)power dissipated in the wire.
b)potential difference across the wire.
C) electrical energy consumed in 2 minutes.

Answer 1

Answer:

Explanation:

As current is given as 4amp

Resistance 60ohm

Thus power dissipation (P) is given as

P=V^2/R

Or P=i^2*R

Thus we must use the 2nd formulae

Now

P=4*4x60=960Watt

Now for potential diff(V) we must use the 1st formulae.

P=V^2/R

960=V^2/60

V^2= 960x60

V=240volt

Now power=rate of change of energy per unit time

Power=energy/time

960=energy/(2/60)

Energy =130J

Answer 2

Answer:

hey mate

Explanation:

R = 60ohm

I= v^2/R

p= 4×4×60

= 960 W

b. p = v^2/R

960 = v ^2/60

v ^2= 960×60

v = 240 volt

c. power = energy/ time

960 = energy / (2/60)

energy = 130J