A current of 5.0A flows through a flashlight bulb when it is connected to 6.0 V what is the power of this bulb
Answers
Answered by
11
Answer:
= 5.0
= 6.0
=?
= = (5.0 )(6.0 ) = 30 = 3.0*10W
Answered by
0
The power of this bulb is 30 watts
Given:
Electric current 5 A
Voltage 6 V
To find:
Power of the bulb
Solution:
The power of any electrical device = Voltage * Current
So here in this case the power will be = (5*6) = 30 Watts
#SPJ3
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