Question

A current of 5 amp is passed through a coil of resistance 75ohm for 2 minutes.How much heat energy in produced in the coil.Only write the answer.

Answer 1

heat formual,
H=i^2Rt
where i is current, R is resistance and t is time
now,
H=(5)^2(75)(2 x 60) j
=25 x 75 x 120 j
=225000 j =225kj

Answer 2

Given ;
I = 5 A
R = 75 ohm
t = 2 min = 120 sec
H = ?

H = I^2 R t
= (5×5)×(75)×(120)
= 225000 J
= 225 K J
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