Math, asked by kavya16, 1 year ago

Water is flowing at the rate of 10 km/h through a pipe of diameter 14 cm into a rectangular tank which is 70 m long and 22 m wide. Find the time in which the level of water in the tank will rise by 50 cm. (use Π=22/7)

Answers

Answered by Anonymous
5

Let the level of water in the pond rises by 21 cm in t hours.

Speed of water = 15 km/hr

Diameter of the pipe = 14/100 m

Radius of the pipe (r) = 7/100 m

Volume of water flowing out of the pipe in 1 hour

= π r 2 h

= (22/7) x (7/100) x (7/100) x 15000

= 231 m3

Volume of water flowing out of the pipe in t hours = 231 t m3.

Volume of water in the cuboidal pond

= 50 x 44 x (21/100)

= 462 m3 

Volume of water flowing out of the pipe in t hours = Volume of water in the cuboidal pond

So, 231 t = 462

t = 2

Thus, the required time is 2 hours.

Answered by bhoomika05012000
1

Answer:

Step-by-step explanation:

Let the time taken be t hrs.

Since water is flowing at rate of 10 km/hr. So ,we assume height of pipe is 10 km.

Volume of water in pipe in t time =Volume of water in tank

πr^2h*t=l*b*h

t=lbh/πr^2h

(Convert all the units in meter)

t=(70*22*(50/100))/((22/7)*(7/100)*(7/100)*(10*1000))

t=5hrs

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