Physics, asked by SPIDEY2049, 1 year ago

A current of 6 A passes through the wire shown in the Figure. Find the magnitude of magnetic field at point C. The radius is 0.02m μ₀ = 4π x 10⁻⁷T m A⁻¹.

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Answered by abhi178
17
we know , magnetic field due to circular arc of radius , r , angle \theta and current passing through it is i is given by
\qquad\qquad\bf{B=\frac{\mu_0i}{4\pi r}[\theta]}

here, \mu_0 = 4π × 10⁻⁷T m A⁻¹, \theta=3π/2
i = 6A , r = 0.02m

so, B = (4π × 10⁻⁷ × 6)/(4π × 0.02) × 3π/2
B = 6 × 3π × 10⁻⁷/(0.02 × 2)
B = 4.5π × 10⁻⁵T
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