Question

A current of 9.65 A flowing for 10 minutes,
deposits 3.0 g of a metal. The
equivalent weight of
the metal is
(2) 30
18) 50
(4) 96.5
(1) 10​

Answer 1

Explanation:

Wt. of metal deposited=3.0g

Q=i X t

=9.65 X 10 X 60

=5790C

Eq.wt. of metal= Wt. of metal X 96500

Q

= 3 X 96500

5750

=50.34

=50(approx.)

Answer 2

Answer:

50 gram

Explanation:

Wt. of metal deposited=3.0g

Q=i X t

=9.65 X 10 X 60

=5790C

Eq.wt. of metal= Wt. of metal/Q X 96500

= 3/5750X 96500

=50.34

Hence, The atomic mass of the metal is 50 gram.