A current of 9.65 A flowing for 10 minutes,
deposits 3.0 g of a metal. The
equivalent weight of
the metal is
(2) 30
18) 50
(4) 96.5
(1) 10
Answers
Answered by
1
Explanation:
Wt. of metal deposited=3.0g
Q=i X t
=9.65 X 10 X 60
=5790C
Eq.wt. of metal= Wt. of metal X 96500
Q
= 3 X 96500
5750
=50.34
=50(approx.)
Answered by
1
Answer:
50 gram
Explanation:
Wt. of metal deposited=3.0g
Q=i X t
=9.65 X 10 X 60
=5790C
Eq.wt. of metal= Wt. of metal/Q X 96500
= 3/5750X 96500
=50.34
Hence, The atomic mass of the metal is 50 gram.
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