Question

A current of 965 ampere is passed for ‘1’ sec
through ‘1’ lit solution of 0.02N NiSO4 using
Ni electrodes. What is the new concentration
of NiSO4?
1) 0.01 N 2) 0.01 M
3) 0.002 M 4) 0.02 M

Answer 1

Given:

A current of 965 ampere is passed for ‘1’ sec through ‘1’ lit solution of 0.02N NiSO4 using Ni electrodes.  

To find:

What is the new concentration of NiSO4?

Solution:

From given, we have,

A current of 965 ampere is passed for ‘1’ sec through ‘1’ lit solution of 0.02N NiSO4 using Ni electrodes.  

We use the formula,

W = Z×i×t/F

W/Z = i×t/F

W/Z = (965 × 1)/96500 = 1/100 = 0.01

Equivalent of NiSO4 present initially = 1 × 0.02 = 0.02.  

The new concentration of NiSO4 is 0.02 - 0.01 = 0.01  

Therefore, the new concentration of NiSO4 is 0.01 N, option (1) is correct.

Answer 2

option 1 is correct answer