A current of electricity was passed through a series of cells containing silver nitrate and cupric sulphate solutions for a period of 25 minutes, if weight of silver deposited was 0.108g .What would be the weight of copper deposited?
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Answer:
we have,
Ag
+
+e
−
→Ag
w=
96500
E∗I∗t
1.018=
96500
108∗2.5∗t
t=363.8sec
for mass of copper deposited,
w=
n∗96500
E∗I∗t
w=
2∗96500
63.5∗2.5∗363.8
w=0.598g
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