Chemistry, asked by kambleanjali1975, 1 month ago

A current of electricity was passed through a series of cells containing silver nitrate and cupric sulphate solutions for a period of 25 minutes, if weight of silver deposited was 0.108g .What would be the weight of copper deposited?

Answers

Answered by bkspokhrel745

0

Answer:

we have,

Ag

+

+e

−

→Ag

w=

96500

E∗I∗t

1.018=

96500

108∗2.5∗t

t=363.8sec

for mass of copper deposited,

w=

n∗96500

E∗I∗t

w=

2∗96500

63.5∗2.5∗363.8

w=0.598g

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