A cycle moving with velocity of 3 m/s increase its motion with acceleration of 5.0 m/s2, what will be the velocit after 5s and the distance cover
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v=u+at. (first equation if motion)
v=3+5*5
v=28 m/s
v=3+5*5
v=28 m/s
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Velocity after 5s
v = u + at
= 3 + (5 × 5)
= 28 m/s
Distance covered in 5s
S = ut + 0.5at^2
= (3 × 5) + (0.5 × 5 × 5^2)
= 77.5 m
v = u + at
= 3 + (5 × 5)
= 28 m/s
Distance covered in 5s
S = ut + 0.5at^2
= (3 × 5) + (0.5 × 5 × 5^2)
= 77.5 m
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