Question

A cycle tire has moment of inertia = 3 kg / m^2 . It is moved with torque of 6 N / m till 20 sec. Find the work done

Answer 1

Solution ✌️

torque (Ꭲ)=moment of inertia(Ꮖ)×angular acceleration(a)

now.....

a=Ꭲ/Ꮖ

now...

work done=Ꭲwt

=>work done=Ꭲ(at)t

=>work done=Ꭲ(Ꭲ/Ꮖ)t²

=>work done=Ꭲ²t²/Ꮖ

=>work done=6²20²/3=4800 Joule