Question

a cyclic quadrilateral pqrs where PS equals to PQ and angle as PQ is 70 degree find angle psq​

Answer 1

Answer:

⇒  ∠QPR=35o          [ Given ] 

⇒  ∠PRQ=90o         [ Angle inscribed in semi-circle ]

⇒  ∠QPR+∠PRQ+∠RQP=180o  [ Sum of interior angles of triangle is 180o ] 

⇒  35o+90o+∠RQP=180o

∴    125o+∠RQP=180o

∴    ∠RQP=55o

⇒   ∠PSR+∠RQP=180o   [ Sum of pair of opposite angles of cyclic quadrilateral is 180o ]

∴     ∠PSR+55o=180o

∴    ∠PSR=180o−55o

∴    ∠PSR=125o

Step-by-step explanation:

hope its helpful

mark as brainlist

rate with 5 star

and like it

pls follow