a cyclic rhombus is
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circle inside rhombus ... . .. .. . . .. . .
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How do you prove a cyclic rhombus is a square?
it think your question is this. then the answer is :
To prove rhombus inscribed in a circle is a square,we need to prove that either any one of its interior angles is equal to 90° or its diagonals are equal. In the figure,diagonal BD is angular bisector of angle B and angle D. Hence, rhombus inscribed in a circle is a square.
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