Question

A cyclist A started his journey on cycle at 7:30 am at a speed 8 km/hr. B, another cyclist, started from the
point half an hour later but with a speed of 10 km/h. at what time did B overtake A ?
A train 100 m long passes another train coming from annosito din
parallel tra
in what time will they cross each other?
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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Cyclist A started his journey on cycle at 7:30 a.m. at a speed of 8 km/h. After 30 minutes, cyclist B started from the same place but with a speed of 10 km/h. At what time did B overtake A?

A- 8 km/hr

B 10 km/hr

distance traveled by A in 1/2 hour = 4 kms.

x/10 = x-4 / 8

10*(x-4)= 8x

10x-40=8x

10x-8x= 40

2x=40

x=20

They meet after a distance of 20 km.

time taken = distance / speed

20 /10 = 2 hours

B overtakes A at 9.30 am.

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