Question

a cyclist a started his journey on cycle at 7:30 am at a speed 8 km/h .B another cyclist started from the same point half an hour later but with a speed of 10 km/h.at whattime did B overtake A

Answer 1

when the time gets 10 o clock A and B reaches at the same position.
so that after 10 o clock B overtakes A

Answer 2

Given :   A cyclist A started his journey on cycle at 7.30 a.m. at a speed 8 km/hr.

B, another cyclist, started from the same point half an hour later but with a speed of 10 km/hr.

To Find : At what time did B overtake A  

Solution:

Method 1 :

A started his journey on cycle at 7.30 a.m. at a speed 8 km/hr.

Distance covered in 1/2  hr = (1/2) * 8  = 4 km

B started his journey at 8 AM

relative speed of B  = 10 - 8  = 2 km/hr

relative distance to be covered = 4 km

Time taken = 4/2 = 2 hrs

8 + 2 = 10  AM

after 10 AM B overtake A

Method 2 ;

Let say after t hours of 8 AM when B started they meet

A  traveled for t + 1/2  hr

B travelled for t hrs

Distance covered are equal

10t = 8(t + 1/2)

=> 2t = 4

=> t = 2

Hence 8 + 2 = 10 AM

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