Question

A cyclist accelerates at a rate of 7.0 m/s2. How long will it take the cyclist to reach a speed of 18 m/s?

Answer 1

U = 0

V = 18m/s

A = 7 m/s²

T = ( we need to find)

By using, a = v - u / t

Putting the values we get

T = v - u /t

T = 18/7

= 2.5 seconds

Hope it will help you.

Answer 2

Complete Question :

›»› A cyclist starts from rest and accelerates at a rate of 7.0 m/s². How long will it take the cyclist to reach a speed of 18 m/s?

Answer :

›»› 2.5 seconds will it take the cyclist to reach a speed of 18 m/s.

Given :

• A cyclist accelerates at a rate of 7.0 m/s².
• The cyclist reach a speed of 18 m/s.

To calculate :

• The time taken of the cyclist to reach a speed of 18 m/s.

How to calculate?

Here in this question we have to calculate the time taken of the cyclist to reach a speed of 18 m/s. We can use the first equation of motion to calculate the time taken of the cyclist to reach a speed of 18 m/s.

Since, we are provided with the Acceleration produced and the final velocity of the cyclist.

But according to the given information, cyclist moves from rest, i.e, the Initial velocity of the body will be 0, although the Final velocity will have some value.

Here, we concluded that :

→ Initial velocity of the ball is 0 m/s.

Calculation :

From first equation of motion.

→ v = u + at

→ 18 = 0 + 7.0 × t

→ 18 = 0 + 7 × t

→ 18 = 0 + 7t

→ 18 = 7t

→ t = 18 ÷ 7

→ t = 2.5

Hence, 2.5 seconds will it take the cyclist to reach a speed of 18 m/s.