Question

a cyclist accelerates from rest to a velocity of 72 km/hour in 10 seconds .the cyclist is in a straight track .the acceleration of the cyclist is ​

Answer 1

Answer:

As we know to find Acceleration, a= v-u/t

Given,

u= 72 km/h = 72×1000/3600 = 20 m/s

v= 0 m/s

t= 10 s

a=v-u/t

a= 0- 20/10

a= 2m/s²

Explanation:

hope this will be helpful

Answer 2

Given:

A cyclist accelerates from rest to a velocity of 72 km/hour in 10 seconds.

To find:

Acceleration of cyclist ?

Calculation:

First of all, lets convert unit of velocity from km/hr to m/s:

$72 \: km/hr = 72 \times \dfrac{1000}{3600} \: m/s$

$\implies \: 72 \: km/hr = 72 \times \dfrac{5}{18} \: m/s$

$\implies \: 72 \: km/hr = 20 \: m/s$

Now, applying Equation of Kinematics:

$v = u + at$

$\implies \: 20 = 0 + a(10)$

$\implies \: 20 =10a$

$\implies \: a = 2 \: m/ {s}^{2}$

So, acceleration of cyclist is 2 m/s².