Question

A cyclist comes to a skidding stop within 10 m . During the process , the force on the cycle due to the road is 250 N and is directly opposed to the motion. How much work does the road do on the cycle.​

Answer 1

Given:-

• Force ,F = -250 N (opposite in direction)

• Displacement ,s = 10 m

To Find:-

• Work done ,W

Solution:-

As we know that Work Done is defined as the product force and displacement.

• W = Fs

Where,

W is the Work Done

F is the Force

s is the displacement

Substitute the value we get

→ W = -250 × 10

→ W = -2500 J

Here, negative sign show that the work is done in opposite directions.

Therefore, the work done is 2500 Joules.

Answer 2

Answer:

Given :-

• Force (F) = -250 N
• Displacement (D) = 10 M

To Find :-

Work done

Solution :-

As we know that work done is the product of displacement and force

$\huge \bf \dag \: W = fs \dag$

Here,

W = Work done

F = Force applied

S = Displacement

$\rule {202}{6}$

W = -250 × 10

W = -2500

Extra storage

Newton - Newton is the unit of force.