Question

A cyclist covers first half of a length with a speed of 5m/s and the second half with a speed of 10m/s. what is the average speed of the cyclist.

Answer 1

▶ Solution :

Given :

▪ A cyclist covers first half of total distance with a speed of 5mps and second half of total distance with a speed of 10mps.

To Find :

▪ Average speed of the cyclist.

Concept :

→ Average speed is defined as ratio of total distance travelled to the total time taken.

→ It is a scalar quantity.

→ If body covers first half of total distance with speed of v1 and second half of total distance with speed of v2 then average speed of body is given by

$\boxed{\bf{\gray{V_{av}=\dfrac{2V_1V_2}{V_1+V_2}}}}$

Calculation :

$\implies\sf\:V_{av}=\dfrac{2(5)(10)}{5+10}\\ \\ \implies\sf\:V_{av}=\dfrac{100}{15}\\ \\ \implies\boxed{\bf{\green{V_{av}=6.67\:mps}}}$

Answer 2

Answer:

Explanation:

average speed =total distance/total time

=L/(L/5+L/10)

=10/3M/S