A cyclist cycles non stop from A to B a distance of 14 km at a certain average speed. If average speed reduces by 1km/h , He takes 1/3 hour more to cover the same distance. Find the signal average speed of the cyclist
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1. 90 \: Km/hr =(90 \times \dfrac{5}{18}) \: m/s= 25 \: m/s
2. 15 \: m/s =(15 \times \dfrac{18}{5}) \: Km/h = 54 \: Km/h
3. 75 \: cm/s =0.75 \: m/s (\because 75 cm=\dfrac{75}{100} \: m =0.75 \: m )
=(0.75 \times \dfrac{18}{5}) \: m/s =2.7 \: Km/h
4. 45 \: Km/h =\dfrac{45 \: Km}{1 \: hr}= \dfrac{(45 \times 1000) \: m}{60 \:min}=750 \: m/min
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