Question

A cyclist driving of 5 m/s picks a velocity of 10 m/s over a distance of 50 m calculate :- (a) Acceleration (b) Time in which the cyclist picks up the above velocity. ​

Answer 1

Explanation:

initial velocity, u = 5m/s

final velocity , v = 10m/s

distance , s = 50m

acceleration, a = ?

time taken , t = ?

Using 3rd eq of motion

${v}^{2} - u^{2} = 2as$

100 - 25 = 2.a.50

75/100 = a

a = 0.75 m/s^2

Using 1st eq of motion

v = u + at

10= 5 + 0.75t

5= 0.75t

t=6.67s

approx 7s