A cyclist goes around a circular track of diameter 105m in 5min. Calculate his speed andvelocity at the end of 7minutes 30econds.
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Answered by
0
Is the question correct?
I think distance and displacement should come in place of speed and velocity..
I think distance and displacement should come in place of speed and velocity..
taz2:
yes its correct i guess
i guess we need to use the formula sn=u+a(n-1/2)
???
which formula is this?
there are two times given
Answered by
8
speed at 5 min is distance by time is equal to
distance is 2πr=2*22/7*52.5=330m
speed=330/5min=330/300=1.1m/sec
whereas speed at end of 7min 30 sec is
speed=330/7.5min=330/450=0.73m/sec
and velocity=displacement/time
so,
v=105/450=0.23m/sec
therefore speed at end of 7.5min is 0.73m/sec
and velocity is 0.23m/sec..
hope it is helpful....
distance is 2πr=2*22/7*52.5=330m
speed=330/5min=330/300=1.1m/sec
whereas speed at end of 7min 30 sec is
speed=330/7.5min=330/450=0.73m/sec
and velocity=displacement/time
so,
v=105/450=0.23m/sec
therefore speed at end of 7.5min is 0.73m/sec
and velocity is 0.23m/sec..
hope it is helpful....
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