A cyclist is cycling at a uniform velocity of 8 m/s for 8 seconds. He then stops paddling and the cycle comes to rest in next ten seconds. Draw the v-t graph and calculate:
(i) the average retardation. (ii) the distance covered with uniform
velocity.
(iii) the distance covered with variable velocity. (iv) the average velocity of the cyclist.
Answers
Given :-
A cyclist is cycling at a uniform velocity of 8 m/s for 8 seconds. He then stops paddling and the cycle comes to rest in next ten seconds
To Find :-
(i) the average retardation. (ii) the distance covered with uniform
velocity.
(iii) the distance covered with variable velocity. (iv) the average velocity of the cyclist.
Solution :-
(i) Average retardation = v - u/t
= 0 - 8/8
= -8/8
= -1 m/s²
(ii) Distance = Speed × Time
Distance = 8 × 8
Distance = 64 m
(iii) Distance covered = Area of triangle
Area of triangle = 1/2 × b × h
Area = 1/2 × 8 × 10
Area = 1/2 × 80
Area = 40 m²
(iv) Average velocity = Displacement/Time
Avg. Velocity = 64 + 40/8 + 10
Avg. velocity = 104/18
Avg. velocity = 5.76 m/s
Answer:
Explanation:A cyclist is cycling at a uniform velocity of 8 m/s for 8 seconds. He then stops paddling and the cycle comes to rest in next ten seconds
To Find :-
(i) the average retardation. (ii) the distance covered with uniform
velocity.
(iii) the distance covered with variable velocity. (iv) the average velocity of the cyclist.
Solution :-
(i) Average retardation = v - u/t
= 0 - 8/8
= -8/8
= -1 m/s²
(ii) Distance = Speed × Time
Distance = 8 × 8
Distance = 64 m
(iii) Distance covered = Area of triangle
Area of triangle = 1/2 × b × h
Area = 1/2 × 8 × 10
Area = 1/2 × 80
Area = 40 m²
(iv) Average velocity = Displacement/Time
Avg. Velocity = 64 + 40/8 + 10
Avg. velocity = 104/18
Avg. velocity = 5.76 m/s