Question

A cyclist is going up a slope of 30° with a speed of 3.5 m/s. If
he stops pedalling, how much distance will he move before
coming to rest? (Assume the friction to be negligible).​

Answer 1

Answer:

displacement before rest= 1.225m

Step-by-step explanation:

see here retardation will be gsin30° which will be pulling the cyclist down.

and now as he stops pedalling we will take initial velocity u as 3.5 m/s and final velocity as 0.

then we should apply our third equation of motion which is

v²=u²+2as

since it is retarding motion therefore

0=3.5² - 2gsin30°.displacement(x)

2*10*1/2*x=12.25

x=12.25/10

x=1.225m

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Answer 2

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