A cyclist is travelling at 15m/s. She applies brakes so that she does not collide with a wall 15 m away. What deceleration must she have
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In this question we will calculate the negative acceleration/deceleration, as follows:
Kinematic equations:
SUVAT-- s-displacement, u-initial velocity, v-final velocity,a- acceleration, t-timev=u + atv2 = u2 + 2ass=1/2(u+v)ts=ut + 1/2at2
Her initial velocity, u is 15m/s
Her final velocity is, v 0m/s (since she stops)
Displacement is, s 15m
Hence the acceleration, a :
v2=u2 + 2as
0=15^2 + 2 x a x 15
0=225 + 30a
30a= -225
a = -225/30
a= -7.5 m/s
Therefore she has to decelerate at the rate of 7.5m/s2
Answered by
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Answer:
Initial velocity, u=15m/s Final velocity, v=0m/s Distance, s=15m Acceleration, a=? So, deceleration is 7.6 m/s2 .
EXPLANATION:-
V^2-U^2=2as
0^2-(15^2)=2a*15
-225=30a
a=-225/30
=45/6
=7.6m/s2
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