Physics, asked by pranaav04, 11 months ago

a cyclist moves in a circular path of radius 10m. It takes him 100 seconds to cover 10 laps of the entire path. What is the velocity of the cyclist (in m/s) at the end of 5 seconds?

Answers

Answered by aristocles
0

path length of one lap is given by

L = 2\pi R

L = 2\pi*10[tex]</p><p>[tex]L = 20\pi

now 10 laps are covered in 100 seconds

total distance moved is given by

D = 10 L = 200\pi

now we have

d = \frac{v_f + v_i}{2}*t

200\pi = \frac{vf + 0}{2}*100

v_f = 4\pi

now acceleration is given by

a = \frac{v_f - v_i}{t}

a = \frac{4\pi}{100}

a = 0.04\pi

now velocity after 5 seconds will be

v_f = v_i + at

v_f = 0 + 0.04\pi* 5

v_f = 0.20\pi = 0.63 m/s

so speed at the end of 5 s will be 0.63 m/s

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