Question

A cyclist moving towards right with an acceleration of 4m/s² at t=0 has travelled 5m moving towards the right at 15m/s². What will be his position at t=2 sec?

Answer 1

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Answer 2

Answer:

The position is 17.6 m.

Explanation:

Given that,

Acceleration = 4 m/s²

Distance 5 m

We need to calculate the velocity

Using equation of motion

$v^2=u^2+2as$

Put the value in the equation

$15^2=u^2+2\times4\times5$

$u^2=15^2-40$

$u^2=185\ m/s$

$u=\sqrt{185}\ m/s$

$u=13.60\ m/s$

We need to calculate the final velocity

Using equation of motion

$v = u+at$

Put the value into the formula

$v =13.60+4\times2$

$v = 21.6\ m/s$

We need to calculate the distance

$D = \dfrac{averege\ speed}{time}$

$D=\dfrac{13.6+21.6}{2}$

$D=17.6\ m$

Hence, The position is 17.6 m.