Question

A cyclist moving with an initial velocity of 4m/s is uniformly accelerated at 3 m/s^2 .Find the distance travelled by the cyclist in 6 seconds..​

Answer 1

Question:-

A cyclist moving with an initial velocity of 4m/s is uniformly accelerated at 3 m/s^2 .Find the distance travelled by the cyclist in 6 seconds..

Answer:- 78m

To Find :- s =?

Formula:-

v = u + at

v^2 - u^2 = 2as

s = ut + 1/2 at^2

Given:-

u = 4m/s

u = 4m/sa = 3m/s^2

t = 6s

s = ?

Explanation:-

s = ut + 1/2 at^2

s = 4 × 6 + 1/2 × 3 × 6 × 6

s = 24 + 54

s = 78m

hope this helps you

Answer 2

We can calculate the distance by the second equation pf motion which states:

S=vit +1/2at²

S= (4)(6)+1/2(3)(6)²

S=24+3/2(36)

S=24+54

S=78 m