A cyclist of mass 40 kg exerts a force of 2oo n to move his cycle. Acceleration is 3msâ’2. Force of friction between road and tyres will be
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Answered by
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mass of a cyclist=40kg
Force=200N
Acceleration=3ms^2
Force of friction=ma
=40×3
=120N
Answered by
18
The force of friction between road and tyres is 120 N.
Explanation:
Given that,
Mass of the cyclist, m = 40 kg
Force acting on the cyclist, F = 200 N
Acceleration of the cyclist,
To find,
The force of friction between road and tyres.
Solution,
For of friction is given by :
f = ma
f = 120 N
or
f = -120 N
So, the force of friction between road and tyres is 120 N.
Learn more,
Second law of motion
https://brainly.in/question/979991
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