Physics, asked by akakumars1665, 1 year ago

A cyclist of mass 40 kg exerts a force of 2oo n to move his cycle. Acceleration is 3msâ’2. Force of friction between road and tyres will be

Answers

Answered by mahekvanjani611
24

mass of a cyclist=40kg

Force=200N

Acceleration=3ms^2

Force of friction=ma

=40×3

=120N

Answered by handgunmaine
18

The force of friction between road and tyres is 120 N.

Explanation:

Given that,

Mass of the cyclist, m = 40 kg

Force acting on the cyclist, F = 200 N

Acceleration of the cyclist, a=3\ m/s^2

To find,

The force of friction between road and tyres.

Solution,

For of friction is given by :

f = ma

f=40\ kg\times 3\ m/s^2

f = 120 N

or

f = -120 N

So, the force of friction between road and tyres is 120 N.

Learn more,

Second law of motion

https://brainly.in/question/979991

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