A cyclist speding at 18km/hr on a level road takes a sharp circular turn of radius 3m without reducing the speed .The coefficient of static friction b/w the tyres and the road is 0.1 .will the cyclist slip while taking the turn?
Answers
Answered by
6
18km/h=5m/s
V^2/r=0.1*g
V^2=0.1*10*3=3
V max =underroot 3=1.732
So yes
V^2/r=0.1*g
V^2=0.1*10*3=3
V max =underroot 3=1.732
So yes
Answered by
14
Given:
Speed = 18 km / hr
Radius = 3 m
The coefficient of static friction between the tyres and the road = 0.1
To find:
Whether the cyclist will slip while taking the turn.
Solution:
First the maximum velocity of the cyclist is calculated,
Maximum velocity = √ μ r g
Where,
μ - coefficient of fiction
r - radius
g - gravity
Hence,
Substitute the values,
Maximum velocity = √ 0.1×3×10
Maximum velocity = 1.732 m/s
The maximum velocity with which cyclist can take the turn without falling or slipping is 1.7 m/s
Calculating the velocity of the cyclist,
18 km/h
In m /s ,
Velocity = 5 m/s
Hence, the cyclist will slip during taking the turn.
The answer is yes.
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