a cyclist starting from the rest accelerates the cycle at the rate of 0.5ms¯² for 5 sec. what is his velocity after 5 sec.
Answers
Answered by
1
u=0
v=?
a=0.5m/s²
t=5s
v=u+at
Therefore
v=0+0.5×5
v=2.5m/s
v=?
a=0.5m/s²
t=5s
v=u+at
Therefore
v=0+0.5×5
v=2.5m/s
saran990:
S I understood
Answered by
0
u=0
a=0.5m/s²
t=5 sec
v=?
a=v-u/t
5/10=v-0/5
5/10*5=v
2.5m/s=v
a=0.5m/s²
t=5 sec
v=?
a=v-u/t
5/10=v-0/5
5/10*5=v
2.5m/s=v
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