factorise √2x^2+3x+√2
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Answered by
102
√2x² + 3x + √2
√2x² + 2x + 1x + √2
√2x (x + √2) + 1 ( x + √2)
(√2x + 1)(x+√2)
=> For factorising we use middle term splitting method here,
So,
in this we have to multiply coefficient of x² to constant term.
Here, √2 × √2 = 2
Now , we have to either by subtract or by adding we have to get 3 in middle .
2 = 2 × 1
so, by adding 2 & 1 we get 3
so, we use 2 and 1 to split the middle term.
√2x² + 2x + 1x + √2
√2x (x + √2) + 1 ( x + √2)
(√2x + 1)(x+√2)
=> For factorising we use middle term splitting method here,
So,
in this we have to multiply coefficient of x² to constant term.
Here, √2 × √2 = 2
Now , we have to either by subtract or by adding we have to get 3 in middle .
2 = 2 × 1
so, by adding 2 & 1 we get 3
so, we use 2 and 1 to split the middle term.
Answered by
48
Hy
√2 x sq + 3x +√2=0
√2x sq + 2x + x +√2=0
√2x(x+√2)+1(x+√2)=0
(√2x+1)(x+√2)=0
x=-1/√2,-√2 Ans
Hope it helps
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