A cyclist starts from centre O of a circular park of radius 1km and moves along the path OPRQO as shown Fig. 4.3. If he maintains constant speed of 10ms–1, what is his acceleration at point R in magnitude and direction?
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Answer:
Since the initial position coincides with the final position. So, the net displacement of the cyclist = zero
Average speed of the cyclist =
Total time taken
Total distance travelled
=
10
OP+PQ+QO
km min
−1
=
20
π+4
×60kmh
−1
=21.4kmh
−1
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