Question

A Cyclist travel a distance of 1 km in first hours , 0.5km in the second hours and 0.3 km in the third hours.Find the average speed of the Cyclist in :-
I) km/hrs
lI) metre/sec.

Answer 1

First add up his total distance traveled = 1.8 km

Divide distance by the hours
(1.8 dived by 3)
Equals 0.6 so the answer for the first one is
0.6km/hrs

For the second one multiply 3*60 which is 180 and now 60*180 which is 10,800 now divide 1,800 with 10,800 which equals to 0.16m/secs
(

Answer 2

avg speed=total distance/total time taken
total dist=1+0.5+0.3=1.8km
total time=3hrs
avg speed=1.8/3=0.6km/h
in m/s=0.6*5/18=1/6m/s