A cyclotron in which protons are accelerated has a flux density of 1.5 70 the variation of frequency of electric field is
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Answer:
The variation of frequency of electric field is 23 MHz
Explanation:
According to the problem the protons within the cyclotrons has the density of 1.570. let the density= d
therefore, d= 1.570
Now let the frequency is s
s= dq/2πm [ where q is the charge of the proton and m is the mass of the proton]
s= 1.570 x 1.6 x 10^(-19)/ 2 π x 1.67 x 10^(-27)
= 0.23 x 10^(-19+27)
= 23 x 10^6
= 23 MHz
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