Question

if a+b=5 and ab = 6 , what is the value of a^2-b^2. Solve it

a. 5
b. 6
c. 10
d. 12​

Answer 1

a+b = 5

a = 5-b

ab = 6

(5-b)*b = 6

5b - b² = 6

b² - 5b + 6 = 0

(b-2)(b-3) = 0

b = 2 or b = 3

Let b = 2, then a = 5 - 2 = 3

Then a² - b² = 3² - 2² = 9 - 4 = 5

Answer 2

Step-by-step explanation:

a+b=5 and ab=6 then

${a}^{2} - {b}^{2} =$

a+b=5

a=5-b

ab=6

(5-b)b=6

5b- b^2=6

b^2-5b+6=0

b^2-3b-2b+6=0

b (b-3)-2 (b-3)=0

(b-3)(b-2)=0

b=3,b=2

ab=6

a×3=6

a=2,a=3

a^2-b^2=(a+b)(a-b)

=(3+2)(3-2)

=5 Answer.