Question

A cylinder contains 68 g of ammonia gas at S.T.P. (i) What is the volume occupied by this gas? (ii) How many moles of ammonia are present in the cylinder? (iii) How many molecules of ammonia are present in the cylinder? [ N = 14 ; H =1 ] plz answer it correctly and don't post irrelevant answers correct answer will definitely be marked as the brainliest

Answer 1

Explanation:

Ammonia gas is N H₃ . Molecular mass = 14 + 3 = 17 amu

Number of moles of Ammonia in 68 gms = 68/17 = 4 moles

1 mole of an ideal gas occupies 22.4 liters at STP

Hence 4 moles occupy 4 * 22.4 = 89.6 liters

Number of molecules present in four moles of an ideal gas at any temperature and pressure = 4 * Avogadro number = 4 * 6.023 * 10^23