Question

A cylinder is open at both ends and made of 3 cm thick metal , the external diameter is 24 cm and height is 168 cm . What is the volume of metal used in making the cylinder? find the weight of cylinder . If 2 cm cube of the metal weight 15 g.​

Answer 1

Answer:

volume of metal=volume of total cylinder-volume of inner cylinder (which is removed)=π[(24/2)^2 - (18/2)^2](H)

So weight will be v(calculated above) × (15/2)

   

i hope it is helpfull

plz mark me as brainlist

and follow me

Answer 2

${\huge{\underbrace{\rm{Question}}}}$

A cylinder is open at both ends and made of 3 cm thick metal , the external diameter is 24 cm and height is 168 cm . What is the volume of metal used in making the cylinder? find the weight of cylinder . If 1 cm cube of the metal weight 15 g.

${\huge{\underbrace{\rm{Answer}}}}$

⠀⠀

Given:

⠀⠀

• Thickness of the metal is 3 cm

• the external diameter of the cylinder is 24 cm

• Height of the cylinder is = 168 cm

⠀⠀

To find:

⠀⠀

• What is the volume of metal used in making the cylinder

• find the weight of cylinder . If 2 cm cube of the metal weight 15 g.

⠀⠀

Solution:

⠀⠀

External diameter of the cylinder is 24

External radius of the cylinder is= $\sf{\dfrac{24}{2}\:cm}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= $\sf{\cancel{\dfrac{24}{2}}\:cm}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= $\sf{12\:cm}$

⠀⠀

Thickness of the cylinder is = 3 cm

⠀⠀

.°. Internal radius of the cylinder is

$\sf{External\:radius\:of\:the\:cylinder- thickness\:of\:the\:cylinder}$

⠀⠀

= $\sf{12-3\:cm}$

⠀⠀

= $\sf{9\:cm}$

⠀⠀

We know that,

⠀⠀

⠀⠀⠀⠀$\boxed{\bf{\pink{Volume\:of\:cylinder=πr^{2}h}}}$

⠀⠀

Where,

⠀⠀

• r = radius of the cylinder

• h = height of the cylinder

• π = $\sf{\dfrac{22}{7}}$

⠀⠀

$\sf{Volume\:of\:the\:external\:part\:of\:the\:cylinder\:is=πr^{2}h}$

⠀⠀

= $\sf{\dfrac{22}{7}×12×168\:cm^{3}}$

⠀⠀

= $\sf{22×12×24\:cm^{3}}$

⠀⠀

= $\sf{6336\:cm^{3}}$

⠀⠀

$\sf{Volume\:of\:the\:internal\:part\:of\:the\:cylinder\:is=πr^{2}h}$

⠀⠀

= $\sf{\dfrac{22}{7}×9×168\:cm^{3}}$

⠀⠀

= $\sf{22×9×24\:cm^{3}}$

⠀⠀

= $\sf{4752\:cm^{3}}$

⠀⠀

.°. The volume of metal used in making the cylinder is

⠀⠀

$\sf{\implies (Volume\:of\:external\:part)-(Volume\:of\:internal\:part)}$

⠀⠀

$\sf{\implies (6336-4752)\:cm^{3}}$

⠀⠀

$\sf{\implies 1584\:cm^{3}}$

⠀⠀

Now,

given that, 1 cm³ metal = 15 g

.°. 1584 cm³ metal= 5 × 1584 cm³ = 23760 cm³

⠀⠀

Therefore,

⠀⠀

• Volume of metal used in making the cylinder is 1584 cm³

⠀⠀

• the weight of cylinder is 23760 If 2 cm cube of the metal weight 15 g.

⠀⠀

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬