a cylinder is open at one end the external diameter is 10 centimetre and thickness 2 CM if the height is 8cm how will be the capacity of cylinder and the volume of metal used
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Answer:
R=5cm
r=3cm. h=8-2=6cm
capacity= πr 2h=22/7 x 3^2 x6
=169.7cm3. Ans
volume of metal=
πR2H-πr2h
π(R2 H-r2h)
22/7(25x8-9x6)
22/7(200-54)
22/7 x 146=458.857cm3. Ans
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