Question

a cylinder is open at one end.The external diameter is 15 cm and its thickness is 3 CM. if the height of the cylinder is 11 cm and if 1 cm cube weighs 9 gram find :- 1 )the capacity of cylinder
2) weight of the metal used in cylinder

Answer 1

Answer:Cylinder volume with external Diameter of 15 cm with height of 11 cm

V₁ = πd²h/4 = π x 15² x 11 / 4 = 2475π/4 cm³

Cylinder volume of internal empty space with diameter of 9 cm (2 x 3 mm of thickness reduced) with height of 8 cm (3 cm thickness at bottom reduced and top is open)

V₂=πd²h/4 = π x 9² x 8/4 = 648π/4 cm³

Effective volume of Cylinder material = V₁ - V₂

⇒ (2475-648)π/4 = 1827π/4 = 1827 x (22/7) / 4

⇒ 261 x 22/4 = 261 x 11/2 = 2871/2 = 1435.5 cm³

1 cm³ weighs = 9 gm

1435.5 cm³ weighs = 1435.5 x 9 = 12,919.5 gms

HOPE IT HELPS

Answer 2

hope it helps..uhh:) bt srry 4 bad handwriting..i was in a hurry..thats whyy