Question

a cylinder of a material is 10 cm long and has a cross section area of 2 cm^2 if its resistence along the length be 10 ohm"s what will be its resistance

Answer 1

Length L = 10 cm
Cross-section A = 2 cm2.
Resistance R = 10 ohm

We have R = ρL/A, where ρ is the resistivity.

ρ = RA/L = 10 x 2/10 = 2 ohm. m
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Answer 2

Improved question.

A cylinder of a material is 10 cm long and has a cross section of 2 cm². If it's resistance along the length 10 ohms , what will be it's resistivity?

Solution :

We are given with :

Length of cylinder , L = 10 cm

And Area = 2 cm²

The given resistance = 10 ohm = 10 Ω

We know very well that :

$R = p \ \frac{L}{A}$

From this formula we can find p = RA/L

p = 10×2/10 = 2 ohm - cm = 0.02 ohm - m