Question

A cylinder of base diameter
50mm its projections when The
axis is inclined at 30 to Hp and
The top view of the axis is
perpendicular to vp​

Answer 1

Procedure –

• Draw XY line.
• As cylinder is resting in VP, so circle will be seen in FV and rectangle in TV.
• Draw FV as a circle of 50 mm diameter above XY line at some convenient distance.
• Draw horizontal and vertical axis of circle.
• Divide the circle into 12 equal parts (You can divide it into 8 parts also). Name all the points 1’, 2’, 3’ ,….12’.
• Take the projections of all point into TV.
• Complete the TV taking axis length 60 mm. Draw all the generators of circle.
• Name the TV on both top base as well as bottom base 1, 2, 3 …12.

Stage 2

• As axis is inclined at 30° to XY line the base 1 7 line will be at 60° inclined to XY line.
• So first mark point 7 at some convenient distance on XY line. Then draw line 1 7 at angle of 60°, so that the axis will be inclined at 30°.
• Using compass mark all the points from stage 1 to stage 2 on line 1 7.
• Complete the TV in inclined position using compass.
• Take the horizontal projections of all 12 points 1’, 2’, 3’, …12’ towards right side in FV.
• Take the projections of inclined TV into FV of all the points 1, 2, 3, …12 from both bases top and bottom.
• Intersection of 1 and 1’ will give point 1, Intersection of 2 and 2’ will give point 2, Intersection of 3 and 3’ will give point 3…….up to point 12.
• Half circle from the bottom base will be invisible from point 4’ to 10’. Draw it as a hidden curves.
• Draw a smooth curve passing through remaining points.
• Join end generators.

Answer 2

Answer:

how do you posted the full photo

question to katarnakkhiladi

please answer this question