Question

A cylinder of base diameter of base 60mm and height 80mm is resting on hp in one of its genrators with its axis inclined at 50° to vp. draw its projections

Answer 1

Given :

• Diameter of the cylinder = 60mm

• Height of the Axis  = 80 mm

• Resting in the HP

Procedure :

• Draw XY line.

• As the cylinder is resting in HP, so the circle will be seen in FV & rectangle in TV.

• Draw FV as the circle of 50 mm diameter above the XY line at some convenient distances.

• Draw horizontal &vertical axis of the circle.

• Divide circle in 12 equal parts.

• Take projections of all the point in TV.

• Complete TV taking axis length 60 mm. Draw all generators of the circle.

• Name TV on both the tops base as well as the bottom base 1, 2, 3 .....…12.

Stage 2 :

• As the axis is inclined at the 50° to X-Y line the base 1 7 line will be at 60° inclined to XY line.

• So first mark the point 7 at a convenient distance on the X=Y line. Then draw the line 1 7 at angle of 60°, so that axis will be in inclination at 50°.

• Using the compass mark all points from stage 1 to the stage 2 on the line 1 7.

• Complete TV in the inclined position by using the compass.

• Take horizontal projection of all the 12 points 1’, 2’, 3’, … 12’ towards the right side in the FV.

• Take projections of the inclined TV in-to FV of all points 1, 2, 3,...…12 from the both bases top & bottom.

• Intersection of 1 &1’ will give the point 1, Intersection of the 2 & 2’ will give the point 2, Intersection of 3 & 3’ will give the point 3…….up to the point 12.

• Half of the circle from bottom base will invisible from point 4’ to 10’. Draw it as if it is having hidden curves.

• Draw the smooth curve passing through that the remaining points.

• Join the end generators.

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