Question

A cylinder of height 5 cm and base radius 2 cm. Use the value of 3.14 for π to calculate its curved surface area to the nearest cm2.

Answer 1

$\underline{\pink{Dimensions \:of \:a \: cylider:}}$

$Height (h) = 5 \:cm$

$and \: base \:radius (r) = 2 \:cm$

$\pi = 3.14$

$\red{Curved\:surface \:area \: of \: cylider}$

$= 2\pi rh$

$= 2 \times 3.14 \times 2 \:cm\times 5 \:cm$

$= 62.8 \:cm^{2}$

Therefore.,

$\red{Curved\:surface \:area \: of \: cylider}$

$\green { = 62.8 \:cm^{2}}$

$\green { \approx 63 \:cm^{2} }$

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Answer 2

curved surface area of cylinder is 62.83cm sq.

Given that

Height of cylinder is 5cm

Radius of cylinder is 2cm

To find

Curved surface area of cylinder

Solution

Let r as radius of cylinder

h as height of cylinder

c as curved surface area of cylinder

As we know that

$c = 2 \times \pi \times r \times h$

put

$\pi = 3.14$

hence

$c = 2 \times 3.14 \times 2 \times 5$

by multiplication we get

$c = 62.83 {cm}^{2}$