Question

A cylinder of height 8cm and perimeter of base is 44cm . find its curved surface area​

Answer 1

$\text{\underline{\underline{Given:}}}$

$\sf{Height\:of\:the\: cylinder\:=\boxed{\:8\:cm}}$

$\sf{Perimeter \: of \: the \: base = 2\pi \: r = \boxed{44 \: cm}}$

$\sf{2 \times \frac{22}{7} \times r = 44}$

$\sf{r = \frac{44 \times 7}{22 \times 2}}$

$\sf\boxed{{r = 7 \: cm}}$


$\sf{C. S. A \: of \: cylinder = 2\pi \: rh}$

$\sf{ = 2 \times \frac{22}{7} \times 7 \times 8}$

$\sf{ = 2 \times 22 \times 8}$

$\sf{ = 44 \times 8}$

$\sf\boxed{{ = 352\:cm^{2}}}$


$\text{\underline{Therefore,}}$

$\sf{Curved\:surface\:area\: of \: cylinder \: is \: 352 {cm}^{2}} .$

Answer 2

Hola !!❤

Here is your answer :-✌

$here.. \\ \\ height \: of \: the \: cylinder = 8cm \\ \\ perimeter \: of \: base = 44cm$

We know that ✔
$curved \: surface \: area \: \\ of \: cylinder = 2\pi \: rh$

So, by putting the number as per the formula, we get ✔
$csa = 44cm \times 8cm \\ = 352 {cm}^{2}$

Hope it helps ✔

By :- @Raashi0080✌